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Maximum demand, Please explain.
Have been trying to work this out and as much as i can get most of it. Some things still confuse me. Ok from the PEER workbook Appendix C worsheet D.
Determine the maximum demand of a single domestic electrical installation supplied with single phase having the following load. 19 lighting points 6 10A double socket outets 16 single socket outlets 1 15A socket outlet 1 20A socket outlet 3 50W exaust fans 3 1000W strip heaters 12.4kW range 1 4.6kW instantaneous water heater 4 500W lights for tennis court Ok heres what i undertsand Load group A(i) 19 lighting points= 3A 3X 50W exaust fans = 135? points going from an example in the regs So 3+2+2+2=9? Load group A(ii) 500W lights = non applicable? Load group B(i) 6 double sockets+16 single sockets =22points? 3 x 1000W strip heaters = 3points(using another example in the book ie 1point for one 1000W heater.) where is this info? Load group B(ii) 1 x 15A socket outlet = 10A? Load group B(iii) 1 x 20A socket outlet = 15A? Load group C 12.4kW range = _____ x 05=______Where do i get this info? Load group F - water heater 4.6W = ____A? I hope this makes sense to someone. Help please. |
Re: Maximum demand, Please explain.
Originally Posted by Jockstar
(Post 8631365)
Have been trying to work this out and as much as i can get most of it. Some things still confuse me. Ok from the PEER workbook Appendix C worsheet D.
Determine the maximum demand of a single domestic electrical installation supplied with single phase having the following load. 19 lighting points 6 10A double socket outets 16 single socket outlets 1 15A socket outlet 1 20A socket outlet 3 50W exaust fans 3 1000W strip heaters 12.4kW range 1 4.6kW instantaneous water heater 4 500W lights for tennis court Ok heres what i undertsand Load group A(i) 19 lighting points= 3A correct +2A for fans =5A 3X 50W exaust fans = 135? points going from an example in the regs So 3+2+2+2=9?read footnote c in notes to table c1-add to lights Load group A(ii) 500W lights = non applicable? .75% OF CONNECTED LOad 6.25A Load group B(i) 6 double sockets+16 single sockets =22points? 3 x 1000W strip heaters = 3points(using another example in the book ie 1point for one 1000W heater.) where is this info? FOOTNOTE(i)lees than 10A add to B Load group B(ii) 1 x 15A socket outlet = 10A?}footnote (J) Load group B(iii) 1 x 20A socket outlet = 15A? Load group C 12.4kW range = _____ x 05=______Where do i get this info? 12400/230 =53.9A 54A x 50% 27A Load group F - water heater 4.6W = ____A? 4600/230 x 33.3%= 6.66A I hope this makes sense to someone. Help please. |
Re: Maximum demand, Please explain.
Originally Posted by Lee and Joanne
(Post 8631861)
does this make sense
Please clarify where did you get 2amps for fan. I assume that 19 lights plus 3 x 50w fan total 22 lights = 3A + 2A. is this correct. please give a feed back will be appreciated. thanks |
Re: Maximum demand, Please explain.
:fingerscrossed:
Originally Posted by Askar
(Post 8632246)
Hi ,
Please clarify where did you get 2amps for fan. I assume that 19 lights plus 3 x 50w fan total 22 lights = 3A + 2A. is this correct. please give a feed back will be appreciated. thanks |
Re: Maximum demand, Please explain.
yes that is correct
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Re: Maximum demand, Please explain.
Can neone plz tell that how many questions in total comes in wiring rule exam in peer
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Re: Maximum demand, Please explain.
Thanks mate.:thumbup:
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Re: Maximum demand, Please explain.
Originally Posted by Lee and Joanne
(Post 8631861)
does this make sense
Load group A(ii) 500W lights = non applicable? .75% OF CONNECTED LOad 6.25A |
Re: Maximum demand, Please explain.
Its 4 X 500w = 2000/230 x .75 = 6.25.
hope that explains. |
Re: Maximum demand, Please explain.
Originally Posted by Jockstar
(Post 8631365)
Have been trying to work this out and as much as i can get most of it. Some things still confuse me. Ok from the PEER workbook Appendix C worsheet D.
Determine the maximum demand of a single domestic electrical installation supplied with single phase having the following load. 19 lighting points 6 10A double socket outets 16 single socket outlets 1 15A socket outlet 1 20A socket outlet 3 50W exaust fans 3 1000W strip heaters 12.4kW range 1 4.6kW instantaneous water heater 4 500W lights for tennis court Ok heres what i undertsand Load group A(i) 19 lighting points= 3A 3X 50W exaust fans = 2A total 3+2 = 5A Load group A(ii) 500W lights = Still not sure how you get that. Load group B(i) 6 double sockets+16 single sockets =22points? 3 x 1000W strip heaters = 3points= 22+3=25points so 10A+5A=15A? Load group B(ii) 1 x 15A socket outlet = 10A Load group B(iii) 1 x 20A socket outlet = 15A + base loading of 15A= 40A? Load group C 12.4kW range = 12400/230= 53.9(54) 54x 0.5= 27A Load group E - water heater 4.6W = 4600/230= 20A x 0.33= 6.66A I hope this makes sense to someone. Help please. |
Re: Maximum demand, Please explain.
Originally Posted by Askar
(Post 8638229)
Its 4 X 500w = 2000/230 x .75 = 6.25.
hope that explains. |
Re: Maximum demand, Please explain.
Originally Posted by Jockstar
(Post 8638247)
Ah! Ok. I forgot it was times 4. lol Does the rest look right?
3X 50W exaust fans = 2A total 3+2 = 5A Load group A(ii) 500W lights = 4 x 500W = 2000W/230 x 0.75 = 6.5A Load group B(i) 6 double sockets+16 single sockets =22points? 3 x 1000W strip heaters = 3points= 22+3=25points so 10A+5A=15A? Load group B(ii) 1 x 15A socket outlet = 10A Load group B(iii) 1 x 20A socket outlet = 15A + base loading of 15A= 40A? Load group C 12.4kW range = 12400/230= 53.9(54) 54x 0.5= 27A Load group E - water heater 4.6W = 4600/230= 20A x 0.33= 6.66A So overall total would be 100A? |
Re: Maximum demand, Please explain.
The rest is right except, Group B(iii) is 1x 20 amps socket = 15amps
Total demand is about 85.15amps. |
Re: Maximum demand, Please explain.
Originally Posted by Askar
(Post 8638358)
The rest is right except, Group B(iii) is 1x 20 amps socket = 15amps
Total demand is about 85.15amps. |
Re: Maximum demand, Please explain.
The correct answer is 95.16 amps
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Re: Maximum demand, Please explain.
Originally Posted by shrikrishan
(Post 8639698)
The correct answer is 95.16 amps
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Re: Maximum demand, Please explain.
19 lig point 3amps
6 10 a double skt outlt 16 10a singl skt outlt 15 amps 3 strip heater 1000 watt 1 15amps skt outlet 10 amps 1 20amps skt outlet 15amps 3 exhaust fans 2amps 1 12.4 kw range 27 amps 1 4.6kw instant water heater 6.66amps 4 500watt tennis light 6.50amps total 85.16 amps |
Re: Maximum demand, Please explain.
Originally Posted by shrikrishan
(Post 8639698)
The correct answer is 95.16 amps
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Re: Maximum demand, Please explain.
old one was mistyped mate.
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Re: Maximum demand, Please explain.
Ok have been working through the next few shets of MD. Will put up these sheet by sheet and lets see if I'm right or if you have the same answers. Ok.
Q2 Same category. Determine the maximum demand of a single phase 240V domestic installation. 28 Lighting points 3A+2a = 5A 8m Lighting track 8 x 2A = 16A 13 10A single socket outlets + 9 10A double socket outlets + 2 50W exhaust fans + 1 1200Watts strip heaters = 13+9+2+1=25points so 10A + 5A = 15A 1 14.5KW range 14500/230 = 63 x 05 = 31.5A 1 3.4kW storage H.W.S. 3400/230 = 14.8A 1 3.0kW clothes drier N/A Total = 82.3A Right or wrong? |
Re: Maximum demand, Please explain.
exactly same answer,Thanx
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Re: Maximum demand, Please explain.
Question 3
Determine the maximum demand of the heaviest loaded phase in a domesticv electrical instalation having the following load- 21 Lighting points 3 + 2 = 5A 28 10A single socket outlets + 8 10A socket outlets = 10A + 5A = 15A 1 range(2 hotplates 6kW each and 6.8kW oven) 18800/230=81.73x0.5=40.86A 1 air conditioner- (single phase 4.8kW) 4500/230 = 19.56 x 0.75= 14.67A 1 clothes dryer - ( single phase 4.8kW) N/A 1 washing machine - ( single phase self heating - 3.2kW) N/A 1 3phase instantaneous water heater (5.3kW per phase) 5300/230 = 23 x 0.333= 7.67A per phase 1 3 phase motor rated at 7.5A per phase = 7.5A per phase Total 90.7A Right or wrong? |
Re: Maximum demand, Please explain.
Originally Posted by Jockstar
(Post 8645528)
Ok have been working through the next few shets of MD. Will put up these sheet by sheet and lets see if I'm right or if you have the same answers. Ok.
Q2 Same category. Determine the maximum demand of a single phase 240V domestic installation. 28 Lighting points 3A+2a = 5A 8m Lighting track 8 x 2A = 16A 13 10A single socket outlets + 9 10A double socket outlets + 2 50W exhaust fans + 1 1200Watts strip heaters = 13+9+2+1=25points so 10A + 5A = 15A 1 14.5KW range 14500/230 = 63 x 05 = 31.5A 1 3.4kW storage H.W.S. 3400/230 = 14.8A 1 3.0kW clothes drier N/A Total = 82.3A Right or wrong? 28 Lighting points 3A+2a = 5A 8m Lighting track 8 x 2A = 16A 2 50W exhaust fans = 2 ie total points is 28+ 16 + 2 = 46points 3A+2A+2A = 7A see egin reg C2.3.2.1 load group A(1) 7A+15A+31.52A+14.78A Total 68.3Amps Please let me know if this correct. |
Re: Maximum demand, Please explain.
Originally Posted by Askar
(Post 8646029)
For question 2 Max Demand I have got, total 68.3.
28 Lighting points 3A+2a = 5A 8m Lighting track 8 x 2A = 16A 2 50W exhaust fans = 2 ie total points is 28+ 16 + 2 = 46points 3A+2A+2A = 7A see egin reg C2.3.2.1 load group A(1) 7A+15A+31.52A+14.78A Total 68.3Amps Please let me know if this correct. The 16 for the track is not points but amps. |
Re: Maximum demand, Please explain.
Please read note d on pg 358 for lighting
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Re: Maximum demand, Please explain.
Also note in the question the voltage 240 is used.
for lighting track read d pg 358, 2 points per metre of track ie 8 x 2 = 16 points final answer [B]66.41 Amps[/B]. please check, I already check with one of m:fingerscrossed:y mate same answer as mine. |
Re: Maximum demand, Please explain.
Thanx for correcting us askar.yea i hve also chkd again u r right.
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Re: Maximum demand, Please explain.
Determine the maximum demand of a single phase 240V domestic installation.
28 Lighting points + 8m Lighting track + 2 50W exhaust fans = 28+16+2= 46 points. Which is 3+2+2=7A 13 10A single socket outlets + 9 10A double socket outlets + 1 1200 watts strip heaters = 13+9+1= 23 points so that would be 10+5=15A 2 50W exhaust fans 1 1200Watts strip heaters 1 14.5KW range 14500/240 = 60.41 x 0.5 = 30.2A 1 3.4kW storage H.W.S. 3400/240 = 14.16A 1 3.0kW clothes drier N/A Total = 66.36A This is what i get after revising the above. Just wondering where you get the extra 0.5A from? |
Re: Maximum demand, Please explain.
Yes your answer is correct.:thumbup:
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Re: Maximum demand, Please explain.
Originally Posted by Jockstar
(Post 8645952)
Question 3
Determine the maximum demand of the heaviest loaded phase in a domesticv electrical instalation having the following load- 21 Lighting points 3 + 2 = 5A 28 10A single socket outlets + 8 10A socket outlets = 10A + 5A = 15A 1 range(2 hotplates 6kW each and 6.8kW oven) 18800/230=81.73x0.5=40.86A 1 air conditioner- (single phase 4.8kW) 4500/230 = 19.56 x 0.75= 14.67A 1 clothes dryer - ( single phase 4.8kW) N/A 1 washing machine - ( single phase self heating - 3.2kW) N/A 1 3phase instantaneous water heater (5.3kW per phase) 5300/230 = 23 x 0.333= 7.67A per phase 1 3 phase motor rated at 7.5A per phase = 7.5A per phase Total 90.7A Right or wrong? What about this one? |
Re: Maximum demand, Please explain.
Foe Maxmium Demand Question No 3.
I was looking at the example on pg 360. You have to put in 3 phase load and balance it ,the answer they looking for is the max current in the phase. The trick is ensure try to balance the load as close as possiable, I wiil attempt later, let me know if you had worked out. thanks. |
Re: Maximum demand, Please explain.
Originally Posted by Askar
(Post 8648003)
Foe Maxmium Demand Question No 3.
I was looking at the example on pg 360. You have to put in 3 phase load and balance it ,the answer they looking for is the max current in the phase. The trick is ensure try to balance the load as close as possiable, I wiil attempt later, let me know if you had worked out. thanks. |
Re: Maximum demand, Please explain.
Determine the maximum demand of the heaviest loaded phase in a domesticv electrical instalation having the following load-
21 Lighting points 3 + 2 = 5A 28 10A single socket outlets + 8 10A socket outlets = 10A + 5A = 15A 1 range(2 hotplates 6kW/230v =13.04A 6.8kW oven) 6800/230= 14.78A 1 air conditioner- (single phase 4.8kW) 4500/230 = 19.56 x 0.75= 14.67A 1 clothes dryer - ( single phase 4.8kW) see reg pg360 = 10.43A 1 washing machine - ( single phase self heating - 3.2kW) = 6.96A 1 3phase instantaneous water heater (5.3kW per phase) 5300/230 = 23 x 0.333= 7.67A per phase 1 3 phase motor rated at 7.5A per phase = 7.5A per phase arrange into 3 phase RED YELLOW BLUE 5A 10A 5A 13.04A 13.04A 14.78A 6.96A 10.43A 14.67A 7.67 7.67 7.67 7.5 7.5 7.5 Total Red= 50.17 Yellow= 43.64 Blue= 44.62 Max demand red phase= 50.17A I hope this is right,can some one check this please.:fingerscrossed: |
Re: Maximum demand, Please explain.
re balance red= 45.17 yellow = 48.64 blue = 44.62
total demand = yellow phase = 48.64A is it right please any one |
Re: Maximum demand, Please explain.
Hi Has any one done question No 3 on maximum demand.on peer work book
Re: Maximum demand, Please explain. -------------------------------------------------------------------------------- re balance red= 45.17 yellow = 48.64 blue = 44.62 total demand = yellow phase = 48.64A is it right please any one Please reply.:fingerscrossed: |
Re: Maximum demand, Please explain.
Originally Posted by Askar
(Post 8660078)
Hi Has any one done question No 3 on maximum demand.on peer work book
Re: Maximum demand, Please explain. -------------------------------------------------------------------------------- re balance red= 45.17 yellow = 48.64 blue = 44.62 total demand = yellow phase = 48.64A is it right please any one Please reply.:fingerscrossed: |
Re: Maximum demand, Please explain.
Question 4 i got 272.76A , 224.88A and 203.31A. Not sure if these are right. Views and opinions please.
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Re: Maximum demand, Please explain.
BTW the last calulation was worked out a while back. So it may be totally wrong.
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Re: Maximum demand, Please explain.
Q4 is not right,I think,please see example on pg361.
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Re: Maximum demand, Please explain.
Originally Posted by Jockstar
(Post 8647926)
Determine the maximum demand of a single phase 240V domestic installation.
28 Lighting points + 8m Lighting track + 2 50W exhaust fans = 28+16+2= 46 points. Which is 3+2+2=7A 13 10A single socket outlets + 9 10A double socket outlets + 1 1200 watts strip heaters = 13+9+1= 23 points so that would be 10+5=15A 2 50W exhaust fans 1 1200Watts strip heaters 1 14.5KW range 14500/240 = 60.41 x 0.5 = 30.2A 1 3.4kW storage H.W.S. 3400/240 = 14.16A 1 3.0kW clothes drier N/A Total = 66.36A This is what i get after revising the above. Just wondering where you get the extra 0.5A from? If got Ai)28p+16+2=46p= 7A B)13p+18+1= 15A C)30,2A+6,5A=36,7A F) 14,2A total: 72,9A |
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